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Practice MCAT Question - Q49 - Answer!

What is the magnitude of the force acting on a particle of charge 1C traveling with a velocity of 1 m/s in a direction parallel to a magnetic field of 1 T?

A.  0 N
B.  0.5 N
C.  1 N
D.  2 N

The correct answer is (A). F = qvB sin(theta). Sin(theta) = sin 0 5 0. The particle would feel the maximum magnetic force if it traveled perpendicularly to the field.

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