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Practice MCAT Question - Q16 - Answer!

How much work is required to move an electron between two terminals whose potential difference is 2.0 x 106 volts?

A.  3.2 x 10-13 J
B.  8.0 x 10-26 J
C.  1.25 x 1025 J
D.  8.0 x 10-13 J

The correct answer is (A). Work is the product of the magnitude of the charge and the potential difference it is moved through:

W = qV = (2.0 x 106 V) (1.6 x 10-19 C)
     = 3.2 x 10-13 J

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