## Practice MCAT Question - Q32 - Answer!

**What is the current in the circuit shown below?**

**A.**0.5 A

**B.**2.0 A

**C.**6.0 A

**D.**12 A

*The correct answer is (B). The three resistors are connected in series so R*

_{tot}= Sum(R) = 6 Ohms. From Ohm’s law, V_{tot}/ R_{tot}= I_{tot}= 12V / 6 Ohms = 2A.**Check The Sidebar For Another**

**Practice MCAT Question**

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