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Practice MCAT Question - Q52 - Answer!

What is the expression for the momentum, p, of a charged particle going through a mass spectrometer?

A.  p = qrB
B.  p = qmB
C.  p = qv2
D.  p = qvB

The correct answer is (A). From F= FB we get mv2/r = qvB. Momentum is p = mv = qrB.

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