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MCAT Question A Day - 2/18/14 - Answer!

A ball is thrown vertically upward with an initial velocity of 40.0 meters per second. What will be its velocity after 2.00 seconds?

A.  20.4 m/s
B.  9.80 m/s
C.  49.0 m/s
D.  80.0 m/s

The correct answer is (A). v = v0+ at. Estimate the acceleration due to gravity using a = -g = -9.8 m/s2 ~ -10 m/s2. The velocity is approximately:

v = 40.0 m/s - 10 m/s2 (2s)
   = 40m/s -  20m/s = 20m/s

The closest choice to 20 m/s is choice (A).

v = 40.0 m/s - 9.80 m/s2 (2s) = 20.4 m/s

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