## MCAT Question A Day - 4/1/14 - Answer!

**A student wishes to find the solubility of Ba(IO**

_{3})_{2}, for which Ksp = 1.6 x 10^{-9}. If x represents the solubility, which equation should she solve?

**A.**1.6 x 10

^{-9}= (x)(x)

**B.**1.6 x 10

^{-9}= (x)(2x)

**C.**1.6 x 10

^{-9}= (x)(x)

^{2}

**D.**1.6 x 10

^{-9}= (x)(2x)

^{2}

^{}

*The correct answer is (D). If “x” equals the solubility of Ba(IO*

_{3})_{2}, then [Ba^{2+}] = x and [IO3^{-}] = 2x.*Want more questions? - Click here to check out our MCAT Question A Day archive*