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MCAT Question A Day - 8/18/13 - Answer!

What is the current in the circuit shown below?

A.  0.5 A
B.  2.0 A
C.  6.0 A
D.  12 A

The correct answer is (B). The three resistors are connected in series so R(tot) = Sum(R) = 6 V. From Ohm’s law, V(tot) / R(tot) = I(tot) = 12V / 6V = 2A.

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